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Rank: Advanced Member
Groups: Member
Joined: 9/6/2007
Posts: 133
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I cannot figure out how to use javascript to check all the nodes in a tree. I know that there is a setting that makes it so that children will be checked when parent is checked, but I am dealing with 4 separate treeviews, and I want a single javasript function to check all nodes for all 4.
This is far as I can get:
function CheckAllExcelExport()
{
//Get the grid object
var tree = eo_GetObject("ctl00_main_TreeViewExcelExport");
//how to loop through all nodes?
//node.setChecked(1);
}
THANK YOU.
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Rank: Administration
Groups: Administration
Joined: 5/27/2007
Posts: 24,193
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Hi, You would just write a function and call it recursively.
Code: JavaScript
function CheckNode(node)
{
//Check the node itself
node.setChecked(1);
//Check all child nodes
var subGroup = node.getSubGroup();
if (subGroup && subGroup.getItemCount())
{
for (var i = 0; i < subGroup.getItemCount(); i++)
CheckNode(subGroup.getItemByIndex(i));
}
Thanks
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Rank: Advanced Member
Groups: Member
Joined: 9/6/2007
Posts: 133
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There are no child nodes, though. It's just a treeview with all nodes on the same level.
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Rank: Advanced Member
Groups: Member
Joined: 9/6/2007
Posts: 133
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I'm still stumped. I tried the following, but it doesn't work either:
function CheckAllExcelExport()
{
var tree = eo_GetObject("ctl00_main_TreeViewExcelExport");
//Check all child nodes
var subGroup = tree.getSubGroup();
if (subGroup && subGroup.getItemCount())
{
for (var i = 0; i < subGroup.getItemCount(); i++)
CheckNode(subGroup.getItemByIndex(i));
}
}
I must be close..
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Rank: Administration
Groups: Administration
Joined: 5/27/2007
Posts: 24,193
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Hi, var subGroup = tree.getSubGroup() is wrong. You should use: var subGroup = tree.getTopGroup(); You will want to go over the reference at here: http://www.essentialobjects.com/ViewDoc.aspx?t=clientapi_howto.htmlIf you just pull something out of the head without looking the reference, then it's almost for sure that it won't work. Thanks
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