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Rank: Advanced Member
Groups: Member
Joined: 7/6/2011
Posts: 30
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Hi I am trying to use the clientsideonchange event to call a javascript that copies the new value from one editablelabel to another. So if I'm calling the script from label1 to copy the new value of label1 to label2, the value that is actually coppied is the value of label1 BEFORE it was changed. Is it supposed to work this way? My test script is below. Quote:<html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <script id="test" language="javascript"> <!-- function copyvalue() { var editableLabel1 = eo_GetObject("EditableLabel1"); var editableLabel2 = eo_GetObject("EditableLabel2"); var Label1Value = editableLabel1.getValue(); editableLabel2.setValue(Label1Value); } --> </script> <title></title> </head> <body> <form id="form1" runat="server"> <div> EditableLabel1: <eo:EditableLabel ID="EditableLabel1" runat="server" ClientSideOnChange="copyvalue" Hint="EditableLabel1" > </eo:EditableLabel> EditableLabel2: <eo:EditableLabel ID="EditableLabel2" runat="server" Hint="EditableLabel2"> </eo:EditableLabel> </div> </form> </body> </html>
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Rank: Administration
Groups: Administration
Joined: 5/27/2007
Posts: 24,195
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Hi, Yes. That's the designed behavior. ClientSideOnChange is called BEFORE the change is accepted with the following argument:
Code: JavaScript
function ClientSideOnChangeHandler(sender, s)
{
//sender is the EditableLabel control that raised this event
//s is the new value
//Inside this function you can modify s and return a new value
//For example, you can have code like this to make sure the
//content of the EditableLabel is no more than 10 characters long
if (s.length > 0)
return s.substr(0, 10);
else
return s;
}
The value returned by this function is then accepted by the EditableLabel and can be queried through getValue. In your case, you can simply add those two arguments into your handler and call editableLabel2.setValue with the second argument. If your function does not return any value, the original EditableLabel will take whatever value you entered. Hope this helps. Thanks!
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Rank: Advanced Member
Groups: Member
Joined: 7/6/2011
Posts: 30
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Fantastic, it works, thank you! (I would never have thought of that :))
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